Recent content by kubekoo

Cool, thanks very much, FinalFantasy! Thansk heaps!

I tried that...... but i got T2=T1 + something, rather than T1/something~ T_T

It's a projectile motion from cambridge, I can do every part, except part a) ii) the shwing T2 thingy~ thanks heaps!~

Super thx for this.

it came from year1994..... if anyone know, please help to understand it.

OMG, that is mad....... thanks so much!!!

the answer to part iii) is N[-pg(p+q) , p^2+q^2+pq+2 ] and part iv) has locus is y = x/2m + 4m^2 +2 ; it says it has restriction of y>3m^2 +2 and x > -2m^3 but i have no idea why....

by doing JR past trial papers, i found some of their locus question asked to restriction of locus?! How do I obtion those restriction? cause they seems like coming out from no where to me T_T

Kooooooooooool.......... i understand Q6 now..... Got out Q10 too~~ thx thx~~~~~~~~!

I can do most of the questions, but when question involve unknow value of V (the initial velocity) and alpha or theta (the initial angle of projection) then i have fully lost... Like for those questions, I can find expression for time of flight , range, maximum height etc... but they are all...

LOL!!!! thanks ~ I understand now!!! I am assuming the definition of a parabola is ~ the point is equal distance from a fixed point (focus) and a fixed line (directrix)~ therefore, PS=PM where M is the point P projected onto the directirx!!!~ Thanks you very much!!!!!!!!!!!!!!!!!!

um~~~ directrix defintion ?!??! i never remember comes across to that before, can u please explain a bit more !!! thx thx thx!!!!

[This is come from 3Units Jones and Couchman Book2 Ex23.5 Q5a and 6c] Q5a) If P(2ap,ap^2) and Q(2aq,aq^2) are points on the parabola x=2at, y=at^2, and S is the focus, prove that PS+SQ=a(p^2 +q^2 +2). and Q6 i know how to do the first 2 parts, a) A stright line through T(0,-a) cuts...

4 Mixed Questions! Q1. A is the point (-2,0) and B the point (2,0). A point P moves such that AP=3PB. Prove that the locus of P is a circle whose equation is x^2 + y^2 -5x +4 = 0 and find the centre and radius of this circle. (This part already done, the following part is the part that I...

Sorry, i didnt' realise that Q1 can be that easy~ and question two~ well~ i never really understand how to read bearings~ so yeah!! ~ thx anyways~