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I tried that...... but i got T2=T1 + something, rather than T1/something~ T_Twanton-wonton said:I didn't do the question, but I think you need to solve for the two x values for that particular y value which corresponds to T1. Then you play around with that.
Cool, thanks very much, FinalFantasy!FinalFantasy said:y=(-1\2)gt²+Utsin@
x=Utcos@
T1=2U\g (sin@-cos@)---->2U\g=T1\(sin@-cos@)
at T2, y=0
0=(-1\2)gt²+Utsin@
(1\2)gt=Usin@
T2=2Usin@\g
=T1sin@\(sin@-cos@)
=T1\cosec@(sin@-cos@)
=T1\(1-cot@)