You have
ax+bx=40 and a+x=2(b+x)
Using the second equation express x in terms of a and b.
Factorise the first equation and sub in for x. Now think about possible factors of 40.
Second question: ab+ba (where a and b are digits of your two digit number).
Your sum is then 10a+b +...
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In that case let angle BAX=\alpha and we easily get the following angles.
XAC=60-\alpha
ACX=60+\alpha
Without loss of generality let AB=AC=BC=1.
Then, using the sine rule
BX=\frac{\sin \alpha}{\sin 60}
XC=\frac{\sin(60- \alpha)}{\sin 60}
AX=\frac{\sin(60+...