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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Not sure where to go from here: I have: P(x) = (x-p)Q(x) + p^3 P(x) = (x-q)Q(x) + q^3
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread I get it now. Thanks.
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread I understand David's working up until his box with Now.... Is that just a trick to get a constant with no x in it? And also, why did you multiply through by 2x + 1 in the next line? Didn't you divide through a few steps...
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread the answer in the textbook says 1/2 not -5/2
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Need help with part a).
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Not sure how to approach part a).
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Could someone help me with the first part of part b). Not sure how to explain why the time T for the particle to travel to x = 1 is T = Integral ..... I though the e^... should be in the denominator and x^2 in the numerator...
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread I have done part a). Part b) is where I am stuck. Answer to b) : x = 1/2 inverse tan (2t), x --> pi/4 and v = 1/(1 + 4t^2) Also unsure how to show part c) acceleration result. Instead I get accel = -4sin2xcos2x Not...
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Could someone help explain part b) I got part a) out, the answers were v^2 = 2(4 - x^2), root6 cm/s , It starts at x = 2 , so on the first occasion it reaches x = 1, it must be moving backwards. Now part b) answer : -2...
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Could someone help explain part b) I got part a) out, the answers were v^2 = 2(4 - x^2), root6 cm/s , It starts at x = 2 , so on the first occasion it reaches x = 1, it must be moving backwards. Now part b) answer : -2 less...
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread sorry no.
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread a man 1.5m is walking directly towards a street lamp 8 metres off the ground at a speed of 36km/h. i) Find the rate at which the length of his shadow is decreasing ii) Find the speed with which the tip of his shadow is moving...
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Unsure how to answer part c). Do I use the base triangle?
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread I get for a) PC = h and PD = h/root3 I am unsure on how to get part b) I though it would use the base triangle, but we have no angles to use.
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Does that mean there should be more than 2 answers, ie. 3 answers.
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread So in this question part ii), is it necessary to change the domain?? For example, sinx - root3cosx = -1 for 0 < x < 2pi Now 2sin(x + 5pi/3) = -1 ; does the domain change here: ie. does it become 0< x + 5pi/3 < 2pi or does...
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread For 19 part c) I got the correct anwer for i) sinx - root3 cosx = 2sin(x +5/3 pi) Now for part ii) I get the answers - pi/2 and pi/6 however the answer says pi/6 and 3pi/2 Could someone explain part ii)
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread I did part b) and got up to the part where t= 0 or t = root 3 so tan x/2 = 0 or tan x/2 = root 3 so new domain is 0 < x/2 < pi so x/2 = 0 or pi/3 and so x = 0 or 2pi/3 The answer have 0, 2pi/3 and 2pi Not sure why...
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Having troubles with part b. I brought everything to the left and got seca ( seca - 2) = 0 then made seca = 0 or seca = 2 so a = 90, 270, 60 , 300 But the answers says 60 or 300 only. Why isn't 90 or 270 included??
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    Cambridge Prelim MX1 Textbook Marathon/Q&A

    Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread I got the correct answers x = 0, pi, 2pi, pi/4, and 5pi/4 as the textbook answers says. However shouldn't the answers pi and 5pi/4 not be included as if you sub them into cosx then cosx< 0 which is wrong as you stated above ??
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