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but im trying to find an expression for t so i can find the time ... i stated above that i found the distance (x) but cant find time (t)

help? like i could get the distance but cant get the time ...

Cambridge book exercise 7.2 question 2 a particle is moving vertically downward in a medium which exerts a resistance to the motion which is proportional to the square of the speed of the particle. it is released form rest at O and its terminal velocity is V. Find the distance it has...

i cant get this for some reason ... please help dt/dv = 1/(g-kv^2)

we have 2 periods of 4 unit altogether around 2 and a half hours a week (and we are up mechanics) 3 unit - we have 5 periods which is altogether 6 hours a week ( and we got to do binomial theroem and probability)

V=x(x^2+36) dV/dt=3 and we are finding dx/dt V = x^3+36x dV/dx = 3x^2+36 dx/dt = dx/dV * dV/dt (so we would have to invert dV/dx) = 1/(3x^2+36) *3 and so we sub x=11 into 3/(3x^2+36) and so we get dx/dt = 1/133 cm/s btw. next time post in ext 1

damn i just had exam too ... and goddamn one of the conics questions i have done b4 like exactly the same but for some reason when you sit in exam you kinda forget everything... i was so disappointed... i find it hard to study to study for conics ... i think the best thing you can do is just do...

just give it a go ... its not that hard i dont think ... its more about managing work load because if you pick up 4unit you have to do a lot of work or you wont understand anything ... plus one more thing to remember revise frequently ... keep doing questions over and over again ... for me, i...

it doesnt check it again .. 2 unit is in the morning and pdhpe is in the arvo

Re: 2006 Higher School Certificate Timetable damn ... maths 4u, software and maths 3u are on consecutive days ... and why the hell is chemistry so late - this is so bs

for 2 and 3 you just divide the top by the bottom and integrate and for the first one ... let u = x+1/2 ... therefore you will get S (u-1/2)(/u^2+3/4) and you split it up ... and integrate ... im not at home so i cant do all the working out.. i hope that helps

angle B = angle C (equal angles in the same segment) hence points A,B,C,D are concyclic and ABCD is a cyclic quad. is that wat you want bcause from reading all the replies above ppl have been saying the exact thing

is your teacher even a maths teacher ... check your maths book ... there should be diagram some where showing equal angles in the same segment

thanks a lot

cant seem to get this question in the expansion of (2+3x)^n the coefficients of the x^3 and x^4 are in the ratio 8:15. Find n

scan it... then edit it using programs like photoshop or sumthing and go to 'image size' and cut it down to 800x600 and save it as jpg ... it should be around 100 kb each...

uhm ... thanks a lot guys, i didnt think it would be steam cracking but i think the temperature gave it away, the question was : what do you get when you crack ethane at 850 degrees?

it was multiple choice ... i got down methane ... but now its ethene and hydrogen . but i thought methane was the best answer ...

a question in our half yearlies ask what is the products when we crack ethane i originally had this question right but our teacher was persuaded by one of the student, now i have it wrong so i want to make sure ... and also an included explanation is helpful thanks

actually theres another way ... but your way is much easier i think... thanks