Let the roots of the equation x^{3} + ax^{2} + 0x + b = 0 be:
\alpha, \frac{1}{\alpha }, \beta.
Then \alpha\frac{1}{\alpha } (1) + \alpha\beta + \beta\frac{1}{\alpha } = \frac{c}{a} = 0
Also \alpha\frac{1}{\alpha }\beta = \beta = - b
And \alpha + \frac{1}{\alpha } + \beta = - a...