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Re: Immediate Help!!!!!!!!!11 use the perpendicular distance formula |x+3| = 2/5|y+1| 5x+15 =2y+2 and 5x+15=-2y-2 5x-2y+13=0 and 5x+2y+17=0 and i guess you'd have to exclude the point (-3,-1)

Re: Immediate Help!!!!!!!!!11 is it meant to be y=-3??

way too keen for school

yeah i didnt study for mine i remember i didnt do any work all year in history, literally cause i hate history, or atleast australian history on the way into the exam hall i asked my mate to tell me the main points bullshited my way through the exam and got 91 so dont bother studying, waste of...

i know this question is asked very often, but can someone estimate my uai please?? MX1- 1/9 MX2 - 1/2 Chem- 2/9 Phys- 2/19 Jap- 2/3 Eng- about 20/about70 and my school rank is low 300's thank

Re: maths again yeah either way works your ways the way i did it

Re: maths again thats just the perp. distance formula but its for the 1st question youd just asked another question by the time i wrote it out

Re: maths again so you have |x-y| = rt2 rt2 |x-y|=2 so x-y=2 or x-y=-2 so the locus is the lines x-y-2=0 and x-y+2=0

you dont study

Re: maths help needed ASAP only if your a relatively accurate graph drawer i prefer to do it algebraically but depends on what you prefer

o wow are you starting 4 unit maths already?? we didnt start till like 5 weeks into 4th term last year

so have you got the answers red butterfly??

ok so that means the diagonals of the parallelogram OABC intersect at right angles, meaning the that the parallelogram is a rhombus and a rhombus has equal sides therefore |z1|=|z2| EDIT: wait is one of those supposed to be arg(z1+z2)? cause thats what i did so if its not totally...

bit rusty on argand diagrams but ill give it a shot 1. arg(z1+z2)= arg(i+(1/rt2)+i(1/rt2)) =arg ((1/rt2) + i(1+rt2/rt)) = tan-1(1+rt2) =3pi/8 2.a) let O be origin, A be z1, B be z1+z2, Cbe z2 if |z1|=|z2| then OABC is a rhombus therefore the diagonals intersect at right angles so...

Re: maths help needed ASAP wow 87 3 uniters guess you go to a smart school then?? which test did you do?? i think i was doin the western region do you reckon youd get a band 6 ( E4 or whatever its called) for getting 100/120 in 4 unit?? by the way, hope your not too devd with your 3 unit...

Re: maths help needed ASAP well different schools learn topics at a different stages like alot of people learn apps of calculus in yr 11 but it was the last yr 12 topic i learnt so i just figured you mightve been learning it now.. sorry

Re: maths help needed ASAP thats good to hear so are you learning this by yourself?

Re: maths help needed ASAP oh right i got about the same 93/120, made so many stupid mistakes cause i was so tired, easily couldve gotten above 100 i reckon if i hadnt made them how about in 3 unit?? i got 81/84. lost all my marks on stupid mistakes like writing the answer off my calculator...

Re: maths help needed ASAP well if you put tan-1(-rt3) in your calculator you get -60 and then you get the other angles like tommykins said: the angles are negative so you know tan is negative in the 2nd and 4th quadrants, so the angles are 180 -tan-1rt and 360 - tan-1rt3

Re: maths help needed ASAP lol i do that all the time howd you go in ure maths trials??