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In some subjects you can use pencil for diagrams, but not for maths. It'd say at the front if you could use pencil

You cant use pencil/red pen in the exam. Blue and black is your only option

These may be useful, see if you can work them out :) One of the questions (question 6 on page 2) is actually answered in the 2nd link http://www.maths.usyd.edu.au/u/UG/JM/MATH1903/r/t3solutions.pdf http://www.maths.usyd.edu.au/u/UG/JM/MATH1903/r/t6-05solutions.pdf

I think it was a joke.....

Differentiation still plays a role in uni :p

yep. If i helps, replace ln3 by a letter like a.

Oh right sorry, read it wrong You can use quotient rule: d/dx ln3/lnx = (-ln3/x)/(lnx)2 = -ln3/x(lnx)2 Or you can use chain rule: d/dx ln3/lnx = d/dx ln3(lnx)-1 = -ln3(lnx)2/x = -ln3/x(lnx)2

Treat the ln3 as a constant, since it is. d/dx lnx/ln3 = 1/(xln3)

log3x = lnx/ln3

No, 1/(2x) = (1/2)x-1 = 2-1x-1

(a) just differentiate with respect to r V = pi.r2.h dV/dr = 2pi.r.h (b) sub in r = 10 and h = 8 to dV/dr

A tangent to the hyperbola y=1/(2x), x>0 cuts the y-axis at the point y=2. Find the gradient of this tangent. Things we know: Point on the tangent: (0,2) Gradient of tangent: m = -1/(2x12), where x1 is the point that the tangent cuts the hyperbola. Equation of tangent: y - 2 = m(x -...

I dont see a condescending tone in there, I think he was implying you'd appreciate it more once you've actually experienced it.

It cant be (b) because thats an impact of aboriginal spirituality on christianity, not the other way around.

Assume n = k is true k3 + (k + 1)3 + (k + 2)3 = 9M For n = k+1 (k + 1)3 + (k + 2)3 + (k + 3)3 = 9M - k3 + (k + 3)3 = 9M - k3 + k3 + 9k2 + 27k + 27 = 9M - 9k2 + 27k + 27 = 9(M - k2 + 3k + 3) = 9N

Last years 2 unit cssa had it, they got you to prove the sin(A + B) one, but they guided you through it.

The equations isnt even a function, i think that eliminates turning points (i think, have to get back on that)

Theres a lot of things that look good until you actually do them :( *cough*Stats*cough*

Yeah well the 2 unit way would just be to mutiply 0.5 n times, so just get rid of the nCn which is just 1 anyways.

In the unlikely chance that i'm still here next year: Semester 1: INFO 2810 - Systems Analysis and Modelling Advanced MATH 2963 - Mathematical Computing and Non-Linear Systems Advanced MATH 2969 - Discrete Mathematics and Graph Theory Advanced SOFT 1902 - Software Development 2 Advanced...