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Isnt this topic in general maths? I recall helping someone with a similar question once.

You can take g = +9.8, you just have to switch the signs for anything going upwards. Both ways work.

Tools need not be part of only one stage. Software development is an ongoing process of change and refinement. If you are talking about creating a data dictionary, then this is most definitely done in the planning stage, as you cannot start any type of implementation before you are yet to even...

yeah well in that situation they took positive as downwards, hence weight is positive, ie +mg. Using the same logic as my previous post, normal force is now -N. Adding up again gives -N + mg = 0, ie N = +mg Thus both weight and normal = +mg. However normal force doesnt always equal mg...

Yes. If you take up as + and down as - : Normal force acts up, so its +N Weight force acts down, so its -mg The sum of the vectors is zero, so + N - mg = 0, hence N = mg.

Its not too late (if my assumption that you are in year 11 is correct). I know people who have dropped to general as late as the trial HSC exams. Procedures vary depending on your school, best probably to see your maths coordinator or if they dont deal with those issues, see whoever does deal...

We studied this issue in one of my units this year. You'll find that the IT jobs that are outsourced are the redundant and boring ones. Managerial and consulting jobs in IT as well as computational science are very hot right now. If you look at the figures youll find that IT management, research...

Yes you do add them. Normal force is upwards, weight is downwards, hence you add them, ie N + (-mg) = 0, so N = mg. If N = -mg, then N + mg = 0, which implies that N and mg act in the same direction (since their sign is the same) which is not true.

Not necessarily from 0 to x, its from c to x, where c can be any constant.

You guys beat me to it, but heres what I was typing anyways: This question requires knowledge of the Fundamental Theorem of Calculus. Using this theorem it can be shown that: where c is a constant. The first question looks exactly like the above, thus the answer is x3 - 3x2 + x - 1...

d/dx etanx = sec2xetanx = etanx/cos2x (sec2x = 1/cos2x) d/dx etanx = etanx/cos2x Anti-derivate both sides: int (d/dx etanx) = int (etanx/cos2x) etanx + C = int (etanx/cos2x) So int (etanx/cos2x) = etanx + C

Theres a number of ways to prove it here: http://www.cut-the-knot.org/pythagoras/index.shtml

If you know that eiθ = cosθ+isinθ, then (cosθ+isinθ)/(cosØ+isinØ) = eiθ/eiØ = ei(θ-Ø) = cos(θ-Ø)+isin(θ-Ø) Very quickly done :)

I guess in numerical solutions they probably would overlook it.

I think you may be referring to copying a question down wrong. eg copying a given equation and mixing the signs. So long as copying down incorrectly does not make the question any easier then its ok.

usyd doesnt offer compsci/maths or IT/maths

er then whats this? http://www.cse.unsw.edu.au/undergrad/programs/csspec.html#A13978

Just a question: Im doing BSc(computer science)/BSc(pure maths) next year, how difficult would it be to fit in a double major for computer science (if possible at all), considering ill be 2nd year next year in maths and with any luck can start on 2nd year computer science units?

Did you like totally ignore the warning that Lazarus posted? Apart from that fact youve posted it twice.

slight error with the signs in the last few lines