Hey a i got a question with a solution on the text book..
but i don't get it.. can anyone pls help..
Differentiate
2x^5(5x+3)^3
Solution:
dy/dx=uv'+vu'
=2x^5 *3(5x+3)^2 *5 + (5x+3)^3 *10x^4 1st Line
=30x^5 *(5x+3)^2 + 10x^4 *(5x+3)^3 2nd Line
=10x^4...