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Here it is I hope.

Here's more info from my treasure chest: damn didnt upload

Hamlet is an excellent text, but I have heard (from hsc marker via someone else) that it really shouldn't be used as a supp text. I would focus on your own texts and mayb keep a working knowledge of Hamlet so you can have it as a back up supp text.

in fact most of the 11 .95s and hundreds from our year would fall into that category. our school does not allow acceleration.

Thank you very much.

Most HSC ext2 graph sketching question, including the example you gave from 2003, should be doable without any calculus.

thats not quite right the sample size you have to consider only includes the combinations RG, GR, and RR, but not GG. I think I get 1/3 too, though I could be wrong cos I suck at probablity.

For 12, sub y = 7 into the equation of flight, then use sums and products of roots in the quadratic in x, as the two roots will be 7 and 14. This method should give you the general expression too Pace_T

not its not just hsc physics it can be asked as a standard projectile motion problem in maths set up 2 columns of equations for both stones, with a = -g. for the first one initial velocity is 0, the second its 20 remember to use t and T for the 2, as the times are different at the end sub...

This is my Antony and Cleopatra essay using Gladiator and Wall Street at supp texts, if anyone is interested.

you cannot use any of the formulae from physics, you will not get the full amount of marks if you do and get the correct answer the only equations you can assume are horizontal acc = 0, vertical acc = -g, unless the question says you can assume the other equations of motions (velocity...

mmm i think you get time of impact by putting y = 0 Then put that time into the equations for vertical and horizontal velocity to get those Then draw a vector triangle to find the combined velocity and the angle of impact

could you give an example to clarify? if you're given the parametrisation, then you already know a, the focal distance and remember that the latus rectum goes through the focus

you've found the area bound by the line, the x-axis and the lines x = 3 and x = 4. To solve, make x the subject: x= y/2 - 1/2. Then integrate from 3 to 4.

I'm guessing you're stuck on the ∫1/((1+sin²x)) part left after the juggling with the cos^2x? Divide top and bottom by cos^2 x, then use the pythagorean identities to simplify the denominator. Then use the substitution u = tanx.

this is from last years data right? great program though i think the scaling for chem might be a little too low

in that case all u can do is accurately graph them, find the point of intersection and give an estimate for x

this isnt an hsc question. are u sure there wasnt more information, like find how many solutions maybe, rather than the solutions themselves?

last year i did antony and cleopatra as core, and used wall street and gladiator as supp texts

there are two possible cases: you chose someone with agrophobia, and someone without: 1/20.19/20 = 19/400 and then the other way round: 19/20.1/20 = 19/400 so prob = 19/400 + 19/400 = 19/200