The rate of change is just dS/dt so you have to differentiate S.
\ \frac{dS}{dt} = 4e^{{2t}}
= 2(2e^{{2t}})
= 2(S-3)
Btw to get the S-3 is 2e^2t, just look at the original equation for S and rearrange.
I'm a little confused as to what indicators are used for what titrations.
Wikipedia tells me:
Strong Acid, Strong Base: Phenolphthalein
Strong Acid, Weak Base: Methyl Orange
Weak Acid, Strong Base: Bromothymol Blue
However other sources are giving conflicting results and after coming...
Re: The Official Cricket Thread
600+? Haha there's no need for that! If they bat that long, they'll bat themselves out of the game and it'll be a draw. They need some good captaincy and an early declaration to give themselves a good chance to bowl Australia out considering rain looming on that...
oh wow those steps were amazingly easy, thanks! wait can someone explain that second line to third line again too! i get the 2^n+1 n! but where does the rest come from?
Sent from my Nexus 5 using Tapatalk
Okay so came across this Integration question from Cambridge in class and nobody knew what we were doing after a while (even the teacher). The first and second bit of the question were fine but that last bit where you have the factorials is what we couldn't get to.
The solution in Cambridge...