re: HSC Chemistry Marathon Archive
Yeah, I need to read the question more carefully. Also, I get what you're saying man and I understand there would be no current but why would there be no voltage? Wouldn't there still be a EMF between the two cells? Or actually, is there no voltage because...
re: HSC Chemistry Marathon Archive
lol I just saw the white texts. Question though man, are those actual observations, besides the first one to do with voltage? Also, why exactly is there no voltage (I have an idea just want to know what you think)?
re: HSC Chemistry Marathon Archive
At the anode: Mg(s)->Mg^(2+)(aq)+2e
The electrons liberated through the oxidation of the magnesium electrode migrate to the cathode through the external wire where they reduce the Fe^(2+) ions in solution.
re: HSC Chemistry Marathon Archive
From the formed iron Fe(s)->Fe^(2+)(aq)+2e.
I showed it in my previous answer here:
Corrosion of iron
Oxidation half-equation: Fe(s)->Fe^(2+)(aq)+2e
Reduction half-equation: O2(g)+2H2O(l)+4e->4OH-(aq)
re: HSC Chemistry Marathon Archive
I couldn't think of any other points so I just put down ones according to my option topic Shipwrecks and Corrosion lol.
re: HSC Chemistry Marathon Archive
a) The anode is the magnesium piece of metal and the cathode is the carbon (graphite) rod.
b) A salt bridge is required to complete the circuit in a galvanic cell and to maintain electrical neutrality in the electrolyte solution of each half cell allowing for...
re: HSC Physics Marathon Archive
Can someone mark my answer to this question: How did Einstein's theory of special relativity and his explanation of the photoelectric effect lead to the reconceptualisation of the model of light?
Here's my answer:
Prior to formulation and popularisation of...
re: HSC Chemistry Marathon Archive
Haber process: N2(g)+3H2(g)->2NH3(g) delta(H)=-92 kJ/mol
Since nitrogen on the left hand side of the equation is in its elemental form its oxidation state is zero as is the oxidation state of hydrogen for the same reason...
Re: MX2 Integration Marathon
Thing is though, by dividing by x at the bottom and bottom then applying x=sqrt(x^2) we are assuming that x>0. So we've restricted the integrand to x>0 I think.
re: HSC Physics Marathon Archive
Can someone mark my answer to this question: Scientists have tried to explain observations of black body radiation using classical wave theory then quantum theory. How does quantum theory satisfactorily explain BBR? (3 marks)
My answer: Classical wave theory...
What are their limitations? Also, why is it that BaCl2 emits a yellow flame whilst Ba(2+) is supposedly meant to give off an apple green flame?
Thanks guys.