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for c) i dont get why its 3!.. like.. ok sit down bob first.. so thats 1 .. then betty can go either right of him.. or 2 places to right of him.. so then thats x 2 and then the others is just x 3 x 2 x 1 so thats 1 x 2 x 3 x 2 x 1.. someone explain to me why this isnt so? does it mean...

Ok started Circle probability now.. one of the first questions on the exercise.. just to make sure im doing it correctly Bob, Betty, Ben, Brad and Belinda are to be seated at a round table. Find how many ways this can be done: a) if there are no restrictions ANSWER=24 b) if Bob is to sit...

Four basketball teams A,B,C and D each consist of 10 players numbered from 1,2,3...10. Five players are to be selected at random from the four teams. Find the probability that of the 5 five players selected a) three are numbered 4 and two are numbered 9 i dont get why what im doing is wrong...

The digits 1,2,3,4 are used to form numbers that may have 1,2,3,4 digits in them. If one of the numbers is selected at random, find the probability that: d) it is odd and greater than 3000 e) it is divisible by 3

I'm back :p Six people are to be divided into two groups, each with at least one person. Find the probability that: a) there will be three in each group b) there will be two in one group and four in the other c) there will be one group of five and an individual ^^ I don't get what...

Last question for the night.. follows the other one What is the probability of selecting no tagged fish on exactly three of the seven days during the week

Ahh geez stuck on the next question =\ A tank contains 20 tagged fish and 80 untagged fish. On each day, four fish are selected at random, and after noting whether they are tagged or untagged, they are returned to the tank. Answer the following questions, correct to three significant figures...

I don't get what you just said there? I do get the answer so thats the important bit out of the way :p You mean cause the denominator within the numerator and denominator will both be the same it should not be counted or something?

for that same question.. probability that d) the Es and Ts are together in one group?

yeah thats right now.. but i dont get why 24 is the top number on the fraction (LOL forgotten the name of the top number on a fraction =\)

13) The letters of KETTLE are arranged randomly in a row. Find the probability that: c) the two letters E are together and the two letters T are together no idea =\ lol.. asking so many probability questions .. argh .. but i feel so much better :p i can answer every question in the past 3u...

Arhh another question.. im doing something wrong and i see what it is but i dont know why its wrong. The digits 3,3,4,4,4 and 5 are placed in a row to form a six-digit number. If one of these numbers is selected at random, find the probability that: d) the number starts with 5 and then the...

could you do i) in your way then?

why is denominator here 52P3 instead of 52C3. For all the other questions in this set of questions the denominator is 52C3...

ahh you got those wrong.. i) 741/1700 and j) 64/425

yeah i get it now.. they just joined the 7! x 8 to make 8!.. another question from a standard pack of 52 cards, three are selected at random. find the probability that: a) they are the jack of spades, two of clubs and the seven of diamonds ANSWERED I'm thinking about this logically...

Well all my questions are from the Cambridge year 12 3u book .. and yeh.. that Bob question was an extension question heh

Cool.. no one seems to think im a total dumbass :p just yet Anyway another question .. from my schools past 3u maths test How many ways can the letters of the word CONNECTION be arranged if all the N's are together? Answer = 10 080 Working is 8! / (2! x 2!) .. i dont get why these numbers...

Let S = {1,3,5,7,9,11,13,15,17,19} be the set of the first ten positive odd integers a) how many subsets does S have? b) how many subsets of S contain at least 3 numbers? c) how many subsets with at least three numbers do not contain 7? d) how many subsets with at least three numbers do not...

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