Re: HSC 2015 4U Marathon
when the speed is q, no side force, we have N_q\cos\phi=mg, N_q\sin\phi=mq^2/r which yields gr=\frac{q^2}{\tan\phi} ....(1)
when the speed is p>q, the side force F is downwards, we have N_p\cos\phi-F\sin\phi=mg, N_p\sin\phi+F\cos\phi=mp^2/r which (by dividing...