y=1+\frac{9}{x^2-9}, $ the denominator $ x^2-9\geq-9, $ hence the fraction $ \frac{9}{x^2-9}\leq-1 $ (when $ x^2-9<0 $) or $ \frac{9}{x^2-9}>0 $ (when $ x^2-9>0 $). therefore the range is $ y\leq0 $ or $ y>1.
but you can actually first sketch the graph using asymptotes and turning points, then...