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  1. M

    probability question 2

    Question: How many ways for 5 DIFFERENT marbles to go in 3 jars so that 2 jars contains 2 marbles and the last jar contains one marble? Solution: 5C2 * 3C2 * 1C1 * 3! / 2! What my problem is: i understand that we firstly choose 2 out of 5, then 2 out of the remaining 3, then 1 out of 1, then...
  2. M

    probability question

    Your method makes total sense, but i have an alternative here which i am in a slight confusion: I have the same denominator being 52C5. For numerator, i have 52C1 to choose the first card, then i have 1 choice out of 3 to complete the pair. However, i have to divide by 2! due to the fact that...
  3. M

    probability question

    Hi all, can someone please help and try and explain how to find the probability of obtaining one pair when being dealt a 5 card hand from a standard pack of 52 cards?
  4. M

    past exam papers

    Thanks. But do you mean the papers are in bored of studies forum or in google? I am pretty sure i've looked through the first 20 pages and couldn't find anything...
  5. M

    past exam papers

    Yeah i've been to this site already, but it has one paper, 2002 half-yearly only. the 2nd link is the webpage for this page, did you put that in by accident?
  6. M

    past exam papers

    im looking for 5.3 maths final exam papers for yr 10. Preferrably selective school eg james ruse, broco or grammar
  7. M

    past exam papers

    Hi all, I am hoping someone can share by uploading some of the year 10 final exam papers that their school has given them, I'm willing to pay for these so please PM me.
  8. M

    Trial paper problem

    thx!!!
  9. M

    Trial paper problem

    Can someone please help? Carrotstick? Deswa? Sean? Math man?
  10. M

    Simple De Moivre's Q.

    z^2=i let z=rcis(x), polar form for i=cis(pi/2) this means r^2 cis(2x) = 1cis (pi/2 +2kpi) therefore equating moduli and arguments gives: r=1, x= (pi/2 +2k pi)/2 where k=0,1 so your answers are z1=cis(pi/4) and z2 = cis(3 pi/4)
  11. M

    Trial paper problem

    Right, thanks my rolpsy! Please help with the rest!!! haha
  12. M

    Trial paper problem

    Hi Frank, I think in your solution you've assumed the car is falling downwards along the line BA, hence you claim resultant force is (mv^2/r) *cos(theta), but i think the resultant force along BA should be 0 as the car should not be sliding up or down
  13. M

    Trial paper problem

    Hi THanks for your help, but here is my working, can you please find out what is wrong?
  14. M

    Trial paper problem

    Hi all, I am studying for my trials and i found these two questions to be unbelievably hard, can someone please lend a helping hand. In the kings 2007 trial: Q5a) I get a "plus" between the RHS terms rather than "minus". Can someone please explain with solutions? Q6a) (i) i had no...
  15. M

    hard cambridge rates question

    The question is: A car is travelling C metres behind a truck, both travelling at a constant speed of V m/s. The road widens L metres ahead of the truck and there is an overtaking lane. The car accelerates at a uniform rate so that it is exactly alongside the truck at the beginning of the...
  16. M

    hard cambridge rates question

    I still dont get it though, especially when the length of the truck is not given??
  17. M

    question 8b (v) in SGS trial

    Question 8 in this paper looks relatively easy, except for 8b(v) which i can't seem to be getting the right answer, i kept getting n< some constant, but clearly n needs to be >some constant. I hope someone can help...
  18. M

    harder 3 unit question

    Can someone help with Q12 on page 266 in bill pender (cambridge) yr 12 3unit please.
  19. M

    hard cambridge rates question

    hi all, i am stuck with question 12 on page 266 in cambrige 3unit year 12 book. can someone help please? Thanks!!
  20. M

    error in the question?

    hi all, please see the attachment, i reckon Q5c) is erroneous as a quintic polynomial needs 5 roots, not 4? Am i correct? Also, just to be super sure, Q6a(ii) we need to do y1 - y2 and not y1 + y2 since y2 is under x-axis correct (y1 is the parabola, and y2 is the semicircle)?
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