Find the derivative of the parabola at each poiints and then use the point-gradient formula to find the eqn of tangents
y = 5/2 x^2
dy/dx = 5x
at x = 2, dy/dx = 10
therefore, the eqn of tangent at (2,10) is y - 10 = 10(x-2) [rearrange into the general form]
at x = -4/5, dy/dx = -4...