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Circle Geometry.
Proved that angle GDB= angle FCB, they proved cyclic quads twice and used perpendicular bisector theorem- jeffwu95
- Post #9
- Forum: Mathematics Extension 2
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Circle Geometry.
I did this at tutor 2 weeks ago too lol- jeffwu95
- Post #7
- Forum: Mathematics Extension 2
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Atar estimate please
probably bring up our school ranked to 50- jeffwu95
- Post #19
- Forum: ATAR & HSC Marks (Guidance, Counsel & Estimates)
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Atar estimate please
YO i go to this mraznboys school. we only have 3U trials left- jeffwu95
- Post #17
- Forum: ATAR & HSC Marks (Guidance, Counsel & Estimates)
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MX1 help! Rates of change
heres the solution for whoever: dv/dt=sqrt(h)/3 9r=0.4h (as they are both related) v=(pi)r^2h/3 v=pi(0.4h)^2.h/4 dv/dh=4pih^2/25 dh/dt=dh/dv . dv/dt dh/dt=25/4pi(h)^2 . sqrt(h)/10 =0.034cm/s- jeffwu95
- Post #12
- Forum: Mathematics Extension 1
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MX1 help! Rates of change
fml i know wat i did wrong, for some reason i changed sqrt(h)/3 to sqrt(h)/10 ye i got ur answer- jeffwu95
- Post #11
- Forum: Mathematics Extension 1
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MX1 help! Rates of change
hmm maybe i made a mistake in calculation imma recheck- jeffwu95
- Post #10
- Forum: Mathematics Extension 1
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MX1 help! Rates of change
Nah the past paper had no answers wasnt sure how to relate r and h so i just said that 9r=3.6h but its probably wrong- jeffwu95
- Post #8
- Forum: Mathematics Extension 1
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MX1 help! Rates of change
how do you get an equation with just r and h- jeffwu95
- Post #6
- Forum: Mathematics Extension 1
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CSSA Economics 2012
I wrote about globalisation, international organisations, australias government and other stuff which i forgot -
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