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whats the answer? i got 0.62L (2.s.f) but i feel like i did it wrong

oops the person who got 0.53 is correct, i didnt include the h20 in the molar mass

I got D, 100g + 14g = 114g, divide by 1.060, you get 107.54 which is the volume of the solution. c = n/v, n = 14/120.366, v = 0.10754. therefore c = 1.08 M (3.S.F)

just c! addition of h20 favours the reverse reaction and therefore makes it more pinl

so u work out the [h+] for both solutions. for number 1, u hav 0.25 of H2SO4, so therefore 0.5 mols of h+ as its diprotic. Or so you think!!! H2SO4 ionizes in two stages, the first is h2s04 -> hso4- + h+, which happens 100% of the time (i.e h2so4 is a strong acid), but the ionisation of hso4 is...

oops it is C, a is 0.0025 i forgot a decimal. silly!!!! but deltah for water is 57kj of heat realeased per mol, and one mol of water requires 1 mol of h+ and oh-, so more mols formed = more temp change :)

im p sure its a, you can eliminate b bc ch2cooh is a weak acid, and then u look at the mols that react, c has 0.02 mols of water formed, d has 0.005, a has 0.025 therefore the heat of combustion is highest for a

are solutions out yet?

i got c bc if u draw it and then draw the inv function it looks like it crosses x = 1 3 times. for the last one i guessed c or d i dont remember

i feel like 2022 wasnt that rough outside of the proj motion and the flights question while this like consistently sucked from the last part of q12

i think that was like the hardest maths ext 1 paper ive ever done... managed to get 60-65+ on like all the trials/past papers and i think id be lucky to scrape a pass

haha i tried using series. i would skip this in an exam i feel like the point at which u even get 1 mark is so much work

is there a solution im so stumped

if u play around on desmos, where u have f(x) be an odd function you can see pretty easily that it's not true

ive literally never learnt how to do binomial proofs so if that comes up im gonna cry

im p sure 360 is also a solution for the trig Q along with 0 and 300, also feel like i got a 90-95 raw depending on how generous they r with working marks slayy

36 or 37 koalas?

my scale was so off lmao

one of the CIP qs was the impact of coral sea on course of the war

expand as Nc0a^nb^0 + Nc1a^n-1B^1 + ... + NcNa^0b^n and then pick a term to = r, and the followign one to = r+1 and divide r+1 by r? im not sure but thats what i would do?