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it's parabolic, ie the parabola passing through points (-2,0,0), (2,0,0) and (0,0,4) might as well put my solution up to my model it turns out to be 4Pi Units cubed Z= 4 - x<SUP>2</SUP>- 4y<SUP>2</SUP> integrating z with respect to y with limits - (1/2)*sqrt(4 -x<SUP>2</SUP>) and...

I made that one with mathematica. maybe k = 4? vague outline: z = 4 - x^2 - 4y^2 integrate z W.R.T. y with limits + / - sqrt(1- x^2/4) then integrate the result with respect to x limits -2 to 2. gets a little messy, but thats 4U :D

I asked my teacher if the following would be ok in exams, he answered: it might cost me marks. Could anyone give their opinion? given dN/dt= k(N-B) find N in terms of t. dN/dt= k(N-B) 1/(N-B) dN = k dt / | 1/(N-B) dN = / / | k dt /...

what about: a= -rw^2 = v^2r w-> omega (angular speed) for centripetal acceleration can I use the concept of 'centrifugal' acceleration in questions?

going off topic here. Jayz: I don't mind, but some of your other friends do mind if you post their real name on forums. and I am too young to be a Mr.. don't mislead people.

A magnet will effect those old monitors in the same way as it effects new ones. if you place the poles parallel to the monitor the distortion is greater, and if one pole is pointing towards the screen and not brought too close, the effect would be less (think of the fields).

just use electromagnets, works better. with the only drawback being a drain on power, which I suppose won't affect you much

made a diagram, hope it helps.

I understand it a little differently, I think that parabola is above the major axis imagine an ellipse. imagine a Parabola of peak height 4 units above the major axis. then fit in the other parabolas.

thanks turtle, was a little confused about 0/0.

Jayz, you must have some expertise to offer on this topic :D, why not share it with us.

I seem to have problems setting out Mechanics solutions, I either write more than required or leave out something (eg quoted a formula, instead of deriving it :( ) are there any general guidelines, such as which formulae could be assumed.

The photoelectric effect just shows that light energy come in discrete "packets". Whether it follows that it is a particle or not depends on your definition of a particle. And the cathode ray experiments are about electrons, not light

Jayz ... adhere to internet conventions, I am identified with my screen name here.

expanding on turtle's point, If you define (a/b) = c if and only if b*c = a you can see that x/0 is not defined (no number would satisfy definition), for non zero x and indeterminated for x=0 (all numbers would satisfy definition).

Wire: dicksmith, $14 buy two different thickness wires (unfortunately quite expensive, there should be cheaper sources, but I don't go around much so can't help you there) core: torus or just one piece of iron. Primary coil 100+ secondary experiment with it you should need more coils than...

seems like we agree on things :P

A torus would be great, better still if you have it in half because the small space in the middle is really annoying when you try to wind the coils around, make sure you take these factors into consideration ;)

I think it is best to have the problems posted on this board, because more of us can read it, learn from them and/or correct any errors.

since your teacher explained it, care to reproduce the explanation for the formula of the GPE? I just hope it is not some vague explanations/shaky extrapolations. The only explanation I saw involves calculus. And why do you think people want more maths in physics?