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This is an excellent resource. Who created it?

13 d ii) x - value of C = (1+2^(1/2))^(1/2) 16 a ii) k = (AB)^(1/2) c = (1/2)ln(B/A) Pardon the horrible typesetting, not very good with LaTex

Absolutely agree with this. Seems like you've got a solid background and the potential to do well in 4U, but don't take it for granted and don't immediately drop to 10 units after you've picked up 4U.

You may need to do some very basic analysis of the forces involved in non-uniform acceleration, and the syllabus actually makes reference to the normal and tangential components of acceleration (note that the tangential component of acceleration is the component that makes the magnitude of...

Using a mac, graphed the parabola on Autograph then took a screenshot and pasted it into keynote (basically powerpoint for mac).

What it would look like looking from above (note same colours represent same features as diagram above):

Look at the parabola in the x-y plane (note that it is a parabola on its side). Say that the point (x, y) lies on this parabola, then the point directly below (x, y) that lies on the parabola is (x, -y). The distance between these two points is 2y, and this is the side length of the triangle.

If you look at the diagram on page 132 notice that the z-axis is usually where you would expect the y-axis to be. Look "from above" at the x-y plane and you can see that the base of the triangle stretches from the top of the parabola, to the x-axis (a distance of y), then to the bottom of the...