yep
ah... i dont think that is clear enough for me lol
To be clear,
A = {n, s, w}
P(A) = blah (from above)
Therefore, A U P(A) = {empty set, n, s, w, {n}, {s}, {w}, {n,s}, {n,w}, {s,w}, {n,s,w}}
P(A U P(A)) = 2^(|A U P(A)|) = 2^11
Hi, can someone please check my working out? :)
With g : R -> R defined by g(x) = x3 - x + 1
a) What is the range of f?
b) Is f onto? Explain.
c) Is f one-to-one? Explain.
My working: let E mean 'is an element of'
a) (-∞, ∞)
b)
Method 1: Draw x3 - x and shift it 1 unit up. Looking at the...
Re: HSC 2014 4U Marathon
So we draw a diagram
Look at vector AB
Now
vec(AC)/vec(BC) = alpha/beta
(v-z)/(w-v) = alpha/beta
v(beta) - z(beta) = (w)alpha - (v)alpha
v(alpha + beta) = (w)alpha + z(beta)
v = (bz+aw)/(a+b) as required!!!
\int f'(x)e^{f(x)}dx = e^{f(x)}+C
Or just use integration by substitution, by letting u = x^2 +3
Basically the same thing... (you prove the top thing by doing u = f(x) and forward on)
Just to quickly bump this thread in-case squar3root doesnt see this:
BE CAREFUL WITH QUESTION 1, TAKE AS LONG AS YOU NEED. IF YOU GET SOMETHING WRONG, YOU LOSE A MARK
^well.. just in-case if you didn't read the instructions in question 1 or if your short-term memory just malfunctions and you...
MAPLETA
The test is so easy if you understand the basics
There is like differentiation with application of chain rule, polynomial remainder/factor theorem, solving inequalities and many more
It is all SIMPLE