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Ah yeah thanks. Subbed into the equation above that lol. Lol teacher always said if f (x) is a factor of g (x) then g (x) | f (x). Thanks for the clarification

Can someone read my messy writing and see why my method didn't work? I understand what they did -- The question is for q5 (d) from: http://4unitmaths.com/2001moriah.pdf Here are the solutions...

me and my friend were thinking of submitting to /r/roastme :lol:

Re: HSC 2015 3U Marathon $ Explanation for Drsoccerball's answer: $ $ Fix the two R's on each end$ R {\_}{\_}{\_}{\_}{\_}{\_}{\_}{\_}{\_}{\_}{\_}{\_} R $ Insert the remaining letters in $ = ^{6}C_{6} $ Can be arranged in 6! ways $ = ^{6}C_{6} * 6! $ But there are two E's...

Re: HSC 2015 4U Marathon I'm not sure. The only ones I saw were glittergal96's and the one I posted above.

[IMG] niiiceee

So is there a solution for this?

Re: HSC 2015 4U Marathon Good solution glittergal96 Also another method was:

Re: HSC 2015 4U Marathon also it should be a + right not a -? :P

Re: HSC 2015 4U Marathon Hmm isn't ab = sin(theta)cos(theta) and similarly for cd? so ab + cd = sin(theta)cos(theta) + sin(phi)cos(phi)? not sin(theta)cos(phi) + sin(phi)cos(theta)

Re: HSC 2015 4U Marathon There's only one solution for ab + cd

Re: HSC 2015 4U Marathon $ Consider the expression, $ (\cos \theta + i \sin \theta )^{2} \equiv \cos 2 \theta + i \sin 2 \theta ( $ by De Moivre's Theorem $ ) \equiv \cos^{2} \theta - \sin^{2} \theta + 2i \cos \theta \sin \theta $ Equating real and imaginary parts of both...

ooohhhh

Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Note that y/x = tanx Aim: show dy/dx = tan (pi/4 + t) Note the tan expansion: tan (a+b) = (tana + tanb)/(1-tanatanb) Hence tan (pi/4 + t) = (1 + tant)/(1-tant) So now your aim is to show: dy/dx = (1+ y/x)/(1-y/x) = (x+y)/(x-y)...

:monkey:

What did you find hard about it? I found Module C the hardest

Re: Year 11 Mathematics 3 Unit Cambridge Question & Answer Thread Differentiating with respect to x means differentiating another variable will give the change in variable with respect to x So differentiating a y will give dy/dx sinx + cosy = 1 Diff. Wrt x d(sinx)/dx + d(cosy)/dx = d(1)/dx ==>...

Re: HSC 2015 2U Marathon A point starts at A(0,0). It forms a staircase by moving to the right, cos(18) metres. It then moves up, cos^(2)(18) metres. Then it moves to the right cos^(3)(18) metres and then moves up cos^(4)(18) metres and so on infinitely. Find the angle that the line connecting...

Re: HSC 2015 3U Marathon On the first turn, do we choose a specific card to turn face down? (hence there are different ways to win)

Re: MX2 2015 Integration Marathon b) $ I $ = \int \frac{x^{2}}{x^4 + 4x^{2}} dx + \int \frac{4}{x^4 + 4x^{2}} dx = \int \frac{1}{x^2 + 4} dx + \int \frac{4}{(x^2 + 2)^2 - 4} dx = \frac{1}{2}tan^{-1} \left ( \frac{x}{2} \right ) - \ln \left ( \frac{x^2 +4}{x^{2}} \right ) + \mathcal{C}...