The quadratic function will be in the form ax^2 + bx + c
(1,0) is when x = 1, y = 0
(1) a+b+c = 0
x = -2
(2) 4a -2b + c = 18
x = 3
(3) 9a + 3b + c = -2
solve simulatenously.
x^2 + 5x -3 = ax^2 + ax + b(x^2+2x+1) + cx
RHS = ax^2 + ax + bx^2 + b2x + b + cx
= (a+b)x^2 + (a+2b+c)x + b
Equation...