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If I'm not mistaken, the chemical reactions in this dry cell are much more complex than what is required by the HSC. However, as stated in Wikipedia: So according to that, NH₃ is not a spectator ion, but are in fact a part of a secondary reaction, if that's what you were asking...

Yes, if the train continues to accelerate at a greater or equal rate to the moment depicted in this picture then yes, you're right. However, this question doesn't specify =(

yeah, i simplified it somewhat but that would be how things would work. Why don't u go get a magnet and a solenoid and play with it?

Have a watch of this video: A current will be induced only when there is a change in magnetic field or in this case a relative movement between the solenoid and the magnet. When the North pole of a magnet moves towards a solenoid, it will induce a current, giving rise to a North Pole at the...

oh my bad, cheers mate heres the new graph: (Hope i didnt make more mistakes lololololol)

y=x+1+1/(x-1) Let's split this graph into y=x+1 and y=1/(x-1) y=x+1 is a straight diagonal line with y intercept of 1 and a positive gradient. (this doesn't really change the question) y=1/(x-1) is a hyperbola with an asymptote at x=1 Then you add the 2 together as seen below: Hope that...

Blue line: original plot Red line: original plot divided by 2, thus half the amplitude Yellow line: (Red line)^4 Thus, no 16. You can find the maximums just by subbing in some numbers into the calculations u did for graph 1. then just guess the general shape of the curve

Given that you have already plotted graph 1, you can see the relationship between graph 1 and graph 3:

1) y=2x/(x^2+1) 3) y=x^4/[(x^2+1)^4] Your basically applying ^4 to graph 1

Thanks for clarifying. I was merely producing a graphic to help people understand.

amirite? (might've exaggerated how far forward the ball goes)

Just do it, chem is awesome