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  1. kawaiipotato

    HSC 2015 MX2 Integration Marathon (archive)

    Re: MX2 2015 Integration Marathon Question: http://imgur.com/r357wc1
  2. kawaiipotato

    16ciii.

    I think it'd be better to say since -1 < x < 1 then x^(infinity) approaches zero
  3. kawaiipotato

    Help with this integral

    The rule is to make the top look like the derivative of the bottom. \int \frac{x}{x^2 - 3x + 4} dx $ Notice that the derivative of the bottom is $ 2x-3 $ So firstly, put a $ '2' $ in front of the x $ $ but if you times it by two, you must divide by 2 to not change the question $...
  4. kawaiipotato

    HSC 2015 MX2 Permutations & Combinations Marathon (archive)

    Re: 2015 permutation X2 marathon What do you mean?
  5. kawaiipotato

    HSC 2015 MX2 Permutations & Combinations Marathon (archive)

    Re: 2015 permutation X2 marathon Why does doing total - vowels together not get the same answer? total together = 12!/(2!2!) vowels together = 5!/(2!2!) * 8! not together =
  6. kawaiipotato

    Rate of Change Q

    Wouldn't it just be a cone, as specified by the question? $ V = $\frac{1}{3}\pi r^2 h,$ where $r = \frac{h}{2}
  7. kawaiipotato

    HSC 2015 MX2 Permutations & Combinations Marathon (archive)

    Re: 2015 permutation X2 marathon dunno if this is MX2 and I don't have the answer lol, just saw this somewhere https://i.imgur.com/0YFCJhC.jpg
  8. kawaiipotato

    HSC 2015 MX1 Marathon (archive)

    Re: HSC 2015 3U Marathon And the definition: ^{n}C_{r} = \frac{n!}{(n-r)!r!} ^{n}C_{0} = \frac{n!}{(n-0)!0!} = 1
  9. kawaiipotato

    HSC 2015 MX2 Permutations & Combinations Marathon (archive)

    Re: 2015 permutation X2 marathon I don't think the condition matters does it? Since theres four possibilities (boy girl) (girl boy) (boy boy) (girl girl) Then its 1/4 But id still think it is 1/2....
  10. kawaiipotato

    HSC 2015 MX2 Permutations & Combinations Marathon (archive)

    Re: 2015 permutation X2 marathon wouldn't the sample space decrease whenw e pick the second one? since there's one less
  11. kawaiipotato

    HSC 2015 MX2 Permutations & Combinations Marathon (archive)

    Re: 2015 permutation X2 marathon Is it \frac{a}{a+b} * \frac{a-1}{a+b-1} + \frac{b}{a+b} * \frac{a}{a+b-1} lol probs wrong
  12. kawaiipotato

    an object's colour dependent on its absorbtion

    How about if instead of the absorption graph, it was replaced with an emission spectrum graph?
  13. kawaiipotato

    an object's colour dependent on its absorbtion

    If an object has almost 100% absorption within the red light wavelength range, and 0% within the green light wavelength range, would we predict the object to have a red colour or a green colour?
  14. kawaiipotato

    HSC 2015 MX2 Permutations & Combinations Marathon (archive)

    Re: 2015 permutation X2 marathon Find the number of selections of 4 letters from the word APPLES answer: 11 b) How many 4 letter words can be made from the letters of the word APPLES answer: 192
  15. kawaiipotato

    Trig

    Try to imagine the sides PH and QH going "up" the 3d plane. The paint drawing is hard to represent it http://imgur.com/69IO4bu
  16. kawaiipotato

    Trig

    $ Draw typical 3d diagram, with a diagonal line representing south to north and and horizontal line representing east to west $ $ Label the base of the flag pole (where those two lines meet) as O and the top of the flag pole as H$ $ Label P to on the left side of the horizontal line (as it...
  17. kawaiipotato

    HSC 2015 MX1 Marathon (archive)

    Re: HSC 2015 3U Marathon f(x) = x^2 + \frac{1}{x} $ For zeroes, let $ f(x) = 0 x^2 = -\frac{1}{x} x = -1 . f'(x) = 2x - \frac{1}{x^{2}} $ For stationary points, let $ f'(x) = 0 x = (\frac{1}{2}) ^{\frac{1}{3}} y = ... ( $ sub into f(x) $) f'(x) = \frac{2x^3 - 1}{x^2 }...
  18. kawaiipotato

    HSC 2015 MX2 Permutations & Combinations Marathon (archive)

    Re: 2015 permutation X2 marathon Five women and four men are to be seated at a round table. (i) In how many ways may this be done without restrictions? answer: 40320 (ii) In how many ways may this be done if no two men are to be seated together? answer: 2880 (iii) If one man and...
  19. kawaiipotato

    HSC 2015 MX2 Permutations & Combinations Marathon (archive)

    Re: 2015 permutation X2 marathon 11 men are waiting at a barber. Three men in particular, A,B,C do not want to sit next to each other. How many ways are possible? answer: 20321280
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