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I was provided with no data for 2U. Nor general, as well. Sorry guys. :/

Okay, original post has been modified.

haha me! :D

i assume this is for 4U. that sounds about right!

Oh yes I shall clarify, for 3U, they are all percentages. Lemme edit the post.

btw, I can not 100% guarantee the accuracy of this data. So yeah... Don't bother sledging me and refuting the data. This is what has been reported to me.... That's all.

Well, it seems like Board of Studies are now letting schools access the raw marks for externals of their students (of course, note they have pretty much always had access to the aligned external marks of their students, but not raw marks...) As a result, for the 2013 HSC, a teacher has let us...

I can only advice on subjects I do - English adv - study guides for the texts you're doing and photocopy them, find good resources/notes on the internets Physics - school will probs give you Jacaranda, but for understanding concepts, Surfing and Physics in Focus is good. For practice...

Great job. Really useful! :D

lol how many times have you asked for an estimate? um between 90 and 93. more towards 90.

i don't think thats possible. not sure will need clarification from someone in the know bout this.

100% right. btw braintic, could you check your PMs when you get time? ty. :)

braintic, check your PMs please.

you only get the insane benefits of latin (either continuers or extension) scaling if you get a hsc mark of like 92+ and to original person, good luck. I do latin (2U and 3U) as well, so I completely understand how its like with the subject combo and latin haha :D GL! :D

Around 96 i think.

less than I wanted and aimed for.

yep thanks kuro - got it out but its very very yucky haha thanks! :D

okay i'll try that. brb :D

Sorry, forgot to attach it - http://postimg.org/image/h4s0x2vpv/ Oh also, Kuro, I PMed you with PPs.

Hi peeps, some help with this q will be most appreciated. So, I got a) out by using d/dx (1/2 v^2) = acceleration. But then when I try b), going nowhere. Tried heaps of ways. OF course, tried the normal way of square-rooting both sides of the result of part a) (well it will be negative...