It will depend on the highest and lowest marks of those respective exams, and your rank relative to first and last.
I can't really say how bad it is because I don't know your cohort, how far are you from 1st in both subjects?
It's just a clarification of what your teachers gave them (for your ease of mind). So just to check that there were no errors in the process of them getting your ranks.
These people tend to guestimate based on raw marks attained by past hsc alumini who bought their raw marks and contributed to the raw marks database (you can find this somewhere on this site). So yes, the bolded is true. The band is specified by your HSC mark which is an average of your aligned...
Everyone has different opinions, let them be... and ATAR is a RANK...
My $0.02: 70-83. [could be complately off here though]
I agree with panda15 about the overestimation, since your school doesn't obtain that many B6s the teachers may often give high marks in class and hence the high...
So although absence of evidence is not evidence for absence, the null result of the M&M experiment supported Einstein's theory of the speed of light being constant [due to its nature to be stationary, permeates all matter, invisible etc].
Hi, I'm aiming for a 97.6+ [just a goal I made at the beginning of the year].
With these ranks and marks how is my estimate looking?
School rank average: 150-200
Final Subject Ranks:
- English Advanced: 10/37
- Mathematics Extension 1: 1/12
- Mathematics Extension 2: 3/3
-...
because the planet (normally this is the satellite) was rotating around the star (central body), and orbital speed = root( Mass central body / radius between the too objects) so it's independent
a) can someone explain 7? the word insulator threw me off a...
b) how do you calculate the threshhold frequency for 20? I just picked d, I shouldve went with b cause I dont think theyll ask a question where both are right...
c) can someone also explain 17?
re: HSC Physics Marathon Archive
I still don't really get this, wouldn't the magnet also affect the other half of the coil?, if you think about it?
so I just needed to divide my answer by 2?