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z^4 - 3z^2 + 1 = 0 Show that the roots are 2cos(Pi/5), 2cos(2Pi/5), 2cos(3Pi/5) and 2cos(4Pi/5). I've got a solution but its pretty long and indirect. I wonder if anybody can come up with a nice way of showing it.

Hi, to anyone that knows tricks of determinant evaluation how would you do these questions? i) factorise | 1 1 1 | | x y z | |x^3 y^3 z^3 | ii) deduce the factors of | 1 1 1 1 | | x y z w | |x^2 y^2 z^2 w^2 | |x^4 y^4 z^4...

Hi, anyone want to explain question 23 of the Ascham 2002 trial: A square sheet of aluminium is held horizontally and then dropped so that it enters a vertical uniform magnetic field. It then leaves the field and continues to fall to the floor. Draw a graph showing the acceleration of the...

This is how the question should have looked, something weird is going on with the database. Hi. I did the James Ruse chemistry trial and I've got a couple of questions for anyone who goes to James Ruse. What was the go with question 28a? You had to choose the gaseous alkane with the highest...