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well i jus checked it 3 times now and i REALLY think its 0.323 (0.9 + 0.1)^20 P(>2) = 1 - P(0) - P(1) - P(2) = 1 - 20C0x(0.9)^20 - 20C1x(0.9)^19x(0.1) - 20C2x(0.9)^18x(0.1)^2 = 0.323 the only reason i can think of the FINAL answer maybe being wrong is the calculator...

the constant was -250 lol

that is def right, well either that or im retarded :) well when x is very small sinx is approx equal to x, thats a rule and as n approaches infinity 2pi/n approaches 0 i.e. 'very small' ( the answer is def (pi^2)/2 ) in Q1. e) i think that integral is way too easy for 4 marks (the...

So I think i got 106/120 raw mark, what would the aligned mark be approx? Other people post up what they know and maybe we can estimate what marks give what scaling for everyone ( btw the very last question was definately (pi^2)/2 , not 0 :D )

well along the lines of what gaoOO said, if you think logically, as n approaches infinity n x sin(pi/2n) = really big number x really small number so you're forgetting the 'really big number' so you can't just assume it goes to zero

Hey does anyone wanna start a discussion of the links between the tempest and pan's labrynth, and just in general pan's labrynth and the imaginative journey. Techniques and examples would be good :) Excuse me while i go and watch pan's labrynth again :o Cheers