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  1. nelsonzheng

    Dry cell chemistry

    If I'm not mistaken, the chemical reactions in this dry cell are much more complex than what is required by the HSC. However, as stated in Wikipedia: So according to that, NH<sub>3</sub> is not a spectator ion, but are in fact a part of a secondary reaction, if that's what you were asking...
  2. nelsonzheng

    2010 HSC question

    Yes, if the train continues to accelerate at a greater or equal rate to the moment depicted in this picture then yes, you're right. However, this question doesn't specify =(
  3. nelsonzheng

    Electromagnetic Induction -- Moving Magnet

    yeah, i simplified it somewhat but that would be how things would work. Why don't u go get a magnet and a solenoid and play with it?
  4. nelsonzheng

    Electromagnetic Induction -- Moving Magnet

    Have a watch of this video: A current will be induced only when there is a change in magnetic field or in this case a relative movement between the solenoid and the magnet. When the North pole of a magnet moves towards a solenoid, it will induce a current, giving rise to a North Pole at the...
  5. nelsonzheng

    More Graphing Help Needed!

    oh my bad, cheers mate heres the new graph: (Hope i didnt make more mistakes lololololol)
  6. nelsonzheng

    More Graphing Help Needed!

    y=x+1+1/(x-1) Let's split this graph into y=x+1 and y=1/(x-1) y=x+1 is a straight diagonal line with y intercept of 1 and a positive gradient. (this doesn't really change the question) y=1/(x-1) is a hyperbola with an asymptote at x=1 Then you add the 2 together as seen below: Hope that...
  7. nelsonzheng

    More Graphing Help Needed!

    Blue line: original plot Red line: original plot divided by 2, thus half the amplitude Yellow line: (Red line)^4 Thus, no 16. You can find the maximums just by subbing in some numbers into the calculations u did for graph 1. then just guess the general shape of the curve
  8. nelsonzheng

    More Graphing Help Needed!

    Given that you have already plotted graph 1, you can see the relationship between graph 1 and graph 3:
  9. nelsonzheng

    More Graphing Help Needed!

    1) y=2x/(x^2+1) 3) y=x^4/[(x^2+1)^4] Your basically applying ^4 to graph 1
  10. nelsonzheng

    2010 HSC question

    Thanks for clarifying. I was merely producing a graphic to help people understand.
  11. nelsonzheng

    2010 HSC question

    amirite? (might've exaggerated how far forward the ball goes)
  12. nelsonzheng

    should i do hsc chem?

    Just do it, chem is awesome
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