A body of mass m is pulled up a smooth incline making an angle of theta with the horizontal, and has an acceleration f.
Find the force that pulls the body.
I get the answer as F=mf+mgsin(theta) but the book answer is F=m(f+sin(theta)
Where did the g go?
The answer in the back of the book is 656 N.
We have to use g=10 m/s^2 and F will equal to 656 N.
Thanks for your response guys/girls. I appreciate it.
Hi, I am new here and need help with this problem.
The combined air and road resistance of a car in motion is proportional to v^2, where v is its speed.
When the engine is disengaged the car moves down an incline making an angle of sin^-1 (1/30) with the horizontal, with a velocity of 30...