1/2 In 3 = In root3 (1 Viewer)

random-1006

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with the integration of e^x / (1 + (e^x)^2 limits 1/2In3 and 0 how does the last step work.


thanks

most likely, you will get e's in your answer

and you will have to use log laws ( remember them??, very important 2 unit stuff) to turn 1/2 ln 3 into ln(sqrt3) ( im guessing you will get a e^ ln(sqrt3), which will be just sqrt3)

then use the property that e^(lnx)= x to simplify your answer

i dont think the actual integration ( you should be very specific with your brackets, there is an open bracket but not a closed one lol) can be done from 3 unit methods so i cnt do it, but im pretty sure that was your question
 
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