2026 progress logbook (2 Viewers)

[ALolly]

today:
- finish hms chapter 2
- physics 8.4
- chem 7.3

 

[Socialism]

I was still in bed trying to sleep until 11 I have 0 motivation rn to study

 

[Socialism]

If I can finish my modern homework today I'll be happy 🫩

 

[ALolly]

today:
- finish hms chapter 2
- physics 8.4
- chem 7.3

oopsie i forgot about this. soo i finished 8.4 for physics, 7.3 for chem and kinda did some hms

 

[ALolly]

today:
- finish 8.5 for physics
- 7.4 for chem
- start chapter 3 for hms

 

[aaliya]

u can do this gurl

 

[Study to success]

today:
- Get a move on with my PIP: do a logbook entry, figure out what im gonna include in my chapter 1, figure out interviews and start research
- Try to work on my DT major work
- Get my math homework done

 

[ALolly]

today:
- finish 8.5 for physics
- 7.4 for chem
- start chapter 3 for hms

donee

 

[ALolly]

today:
- finish chapter 3 for hms
- 7.4 for physics
- 7.5 for chem

 

[Study to success]

today:
- Get a move on with my PIP: do a logbook entry, figure out what im gonna include in my chapter 1, figure out interviews and start research
- Try to work on my DT major work
- Get my math homework done

I didn't do dt but I did start on my pip by figuring out the structure of my chapters and then I talked to my mum about possible candidates for my interview but I still need to make a list and ask others. Then I got like 2 chapters of math done which I never finished from last term and I watched atomi videos so that I know how to do the z score probability stuff cause for some reason my brain was dead when we learnt it

 

[ALolly]

today:
- finish chapter 3 for hms
- 7.4 for physics
- 7.5 for chem

soo i only did physics and i didn't even finish that properly and i kinda touched hms

 

[ALolly]

today:
- ACTUALLY do hms
- FINISH 7.4 and 7.3 for physics
- FINISH mod 7 for chem

 

[Socialism]

Well I still haven't done any work whatsoever... So today I'd like to do a math exercise

Apparently we don't actually have modern homework so I guess I don't need to worry about that lol

 

[Ybot08]

Today's study: Chemistry, Extension History Major Work
Chemistry:
Question that I was thinking over (I asked it)
Hi, I was curious about some of the reaction mechanisms (in this instance, for hydration and dehydration as seen on the flowchart between alkenes and alcohols)

When we were going over hydration and dehydration, we mentioned the role of the catalyst (sulfuric/phosphoric acid). After the water is introduced in hydration, it was discussed that the Hydronium from the dissociated (dilute) acid would be attacked by the nucleophilic C=C pi bond (as it, the hydronium, is electrophilic), the H+ would then go to the now severed pi bond and join the carbon (either, with different likelihoods according to Markovnikov's Rule (Also I'd be interested to learn more about the stuff behind this rule, as LCP was to Collision Theory), making the other side of that old pi bond on the carbon empty leaving it positively charged (carbocation) as the shared electron was taken by the hydrogen. That then caused the water to join to the carbon in a nucleophilic attach, which formed an unstable -OH2+ oxonium ion on the carbon (alkyloxonium, R-OH2+) as a result of one of the oxygen lone pairs being used for a hydrogen, and the electronegativity caused that oxygen to release the proton H+ which went back to the catalyst to 'renew' it, leaving the catalyst sort of as new and turning the alkene into an alcohol.

When we were doing dehydration, we determined that concentrated acid was required, due to it removing water from the equilibrium system and thus trending the alcohol back to an alkene. That seemed a bit weird to me due to the process discussed above.

Skipping any knowledge of the start of this reaction, I'd assume that ok, the Oxygen on the hydroxyl group is nucleophilic so it wants to now attack something electrophilic, ie the hydronium (or would it be literally a proton H+??) produced by the concentrated acid (for the purpose of this I'll assume its H2SO4 as that is what we were taught was the main catalyst for this)

If I pretend I know what I'm talking about, I'd continue logically that: ok, so now the abundant hydronium and amphiprotic/amphoteric substance is sitting around for the reaction. since we discussed the -OH2+ bond to the carbon is extremely unstable due to electronegativity and the charge on the oxygen, why now does a proton go to that bond and cause it to break off as water, and subsequently make the pi bond reform? (Assuming currently that it does release a molecule of water and form a carbocation, but unsure why that is more stable than just losing the proton to reform the hydroxyl group instead of a carbocation). My current understanding is a simplification - that after the water has been broken off it will immediately react with the catalysing acid/dehydrating agent [ie phosphoric acid, sulfuric acid, aluminium oxide (lewis)] removing it from the equilibrium attempting to form, but I don't really understand it fully, or the parts where:

1. the OH2+ oxonium ion reforms with conc. H2SO4 and breaks off as water leaving the carbocation (when in hydration the proton just left, what determines which occurs? - is it the environment of the reaction ie presence of water/acid, that's a guess, pls explain more)
2. The other side, (the proton that joined with one side of the pi bond with the electron in hydration) that is trying to form a pi bond now for the alkene - how does this get resolved? (Conjugate base???)
3. I forgot the question filler gap
4. in hot temps/high pressures such as industry why would we use the extremely unsafe sulfuric acid over safer Al2O3 and H3PO4

P.S. please correct any wrong assumptions/anything else here

Extension History:
write a draft introduction (how pls im cooked)

 

[Study to success]

Today's study: Chemistry, Extension History Major Work
Chemistry:
Question that I was thinking over (I asked it)
Hi, I was curious about some of the reaction mechanisms (in this instance, for hydration and dehydration as seen on the flowchart between alkenes and alcohols)

When we were going over hydration and dehydration, we mentioned the role of the catalyst (sulfuric/phosphoric acid). After the water is introduced in hydration, it was discussed that the Hydronium from the dissociated (dilute) acid would be attacked by the nucleophilic C=C pi bond (as it, the hydronium, is electrophilic), the H+ would then go to the now severed pi bond and join the carbon (either, with different likelihoods according to Markovnikov's Rule (Also I'd be interested to learn more about the stuff behind this rule, as LCP was to Collision Theory), making the other side of that old pi bond on the carbon empty leaving it positively charged (carbocation) as the shared electron was taken by the hydrogen. That then caused the water to join to the carbon in a nucleophilic attach, which formed an unstable -OH2+ oxonium ion on the carbon (alkyloxonium, R-OH2+) as a result of one of the oxygen lone pairs being used for a hydrogen, and the electronegativity caused that oxygen to release the proton H+ which went back to the catalyst to 'renew' it, leaving the catalyst sort of as new and turning the alkene into an alcohol.

When we were doing dehydration, we determined that concentrated acid was required, due to it removing water from the equilibrium system and thus trending the alcohol back to an alkene. That seemed a bit weird to me due to the process discussed above.

Skipping any knowledge of the start of this reaction, I'd assume that ok, the Oxygen on the hydroxyl group is nucleophilic so it wants to now attack something electrophilic, ie the hydronium (or would it be literally a proton H+??) produced by the concentrated acid (for the purpose of this I'll assume its H2SO4 as that is what we were taught was the main catalyst for this)

If I pretend I know what I'm talking about, I'd continue logically that: ok, so now the abundant hydronium and amphiprotic/amphoteric substance is sitting around for the reaction. since we discussed the -OH2+ bond to the carbon is extremely unstable due to electronegativity and the charge on the oxygen, why now does a proton go to that bond and cause it to break off as water, and subsequently make the pi bond reform? (Assuming currently that it does release a molecule of water and form a carbocation, but unsure why that is more stable than just losing the proton to reform the hydroxyl group instead of a carbocation). My current understanding is a simplification - that after the water has been broken off it will immediately react with the catalysing acid/dehydrating agent [ie phosphoric acid, sulfuric acid, aluminium oxide (lewis)] removing it from the equilibrium attempting to form, but I don't really understand it fully, or the parts where:

1. the OH2+ oxonium ion reforms with conc. H2SO4 and breaks off as water leaving the carbocation (when in hydration the proton just left, what determines which occurs? - is it the environment of the reaction ie presence of water/acid, that's a guess, pls explain more)
2. The other side, (the proton that joined with one side of the pi bond with the electron in hydration) that is trying to form a pi bond now for the alkene - how does this get resolved? (Conjugate base???)
3. I forgot the question filler gap
4. in hot temps/high pressures such as industry why would we use the extremely unsafe sulfuric acid over safer Al2O3 and H3PO4

P.S. please correct any wrong assumptions/anything else here

Extension History:
write a draft introduction (how pls im cooked)

That’s very detailed wow

 

[Ybot08]

Yeah rare w I was able to work it out with some advice. got a few more like it though

 

[ALolly]

today:
- ACTUALLY do hms
- FINISH 7.4 and 7.3 for physics
- FINISH mod 7 for chem

donee

 

[ALolly]

today:
- continue physics
- study some hms
- continue with chem

 

[Socialism]

write a draft introduction (how pls im cooked)

 

[ALolly]

today:
- continue physics
- study some hms
- continue with chem

done