MedVision ad

21, 22 of SC 2006 Maths Test (1 Viewer)

schultzy92

New Member
Joined
Nov 11, 2007
Messages
16
Gender
Male
HSC
2009
heyy,
Can someone please explain to me how to question 21 and 22 of the SC 2006 Test,

thanks heaps,
schultzy

and 23 thanks, I think i get it but just to check
 
Last edited:

schultzy92

New Member
Joined
Nov 11, 2007
Messages
16
Gender
Male
HSC
2009
Re: 21, 22 of SC 2006 Test

haha riiite, how could i leave that out... maths thanks
 

stoj19

New Member
Joined
Jul 11, 2007
Messages
24
Gender
Male
HSC
2009
Re: 21, 22 of SC 2006 Test

will download and check it out now......
 

stoj19

New Member
Joined
Jul 11, 2007
Messages
24
Gender
Male
HSC
2009
Re: 21, 22 of SC 2006 Test

Question 22

Sumayia claims that 2 to the power of 2 multiplied by 2 to the power of 3 is 4 to the power of 5

Explain why Sumayia is incorrect.


She is incorrect as she multiplied the bases....(2x2) you add the indices and LEAVE the bases


DOING 21 now
 

stoj19

New Member
Joined
Jul 11, 2007
Messages
24
Gender
Male
HSC
2009
Re: 21, 22 of SC 2006 Test

21 The ratio of $10 notes to $20 notes in my wallet is 4 : 5. There are 27 notes altogether.
What is the total value of the 27 notes?

$10 x 12 - $20 x15

= 120 + 300
= $420

:D
 

militiaman

Member
Joined
Jun 6, 2007
Messages
160
Location
Lake Macquarie
Gender
Male
HSC
2009
Re: 21, 22 of SC 2006 Test

Q. 21

4+5 (the total of the ratios) = 9
27 (the total of the notes)/ 9 = 3

3x4=12
3x5=15

Therefore there are 12 $10 notes and 15 $20 notes, which gives:

12x10=$120
15x20=$300

Total value= $420

Q. 22

2^2 x 2^3 = 2^5 (you add the powers when multiplying, and subtract when dividing)

That's the theory (answer rather) behind it, someone might want to explain it better to fully answer the question.

Q. 23

After talking to my friend I found there are two ways to do this. First the easy way which I didn't think of:

x= double the number that is added to x in M (in this case 4, which gives 8)
7

y= same as above 6

You can do this because the mid-point values are half of what the other values are.

Longer more structured way is following the mid-point formula:

M(x,y) = ((x1+x2)/2 , (y1+y2)/2)
M(3,4) = ((-1+x2)/2 , (2+y2)/2))

So you're working out what will add together then divide to give 3 then same for y to get 4.
 

Rhodes

Member
Joined
Oct 1, 2007
Messages
34
Gender
Male
HSC
2009
Re: 21, 22 of SC 2006 Test

Well for question 22 you really should be doing it this way.
2^2X 2^3= 2^5
4^5= (2^2)^5
Therfore: 4^5= 2^10
Which does not equal 2^5

As for question 23 The above poster is correct
 

stoj19

New Member
Joined
Jul 11, 2007
Messages
24
Gender
Male
HSC
2009
Re: 21, 22 of SC 2006 Test

what about me :(
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top