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3D trig (1 Viewer)

Trebla

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From three collinear points, A, B, and C on the ground, the angles of elevation of the top of a mast are 30 degrees, 45 degrees and 60 degrees respectively. if AB = 90m and BC = 150m, find the exact height of the mast.

I keep getting undefined answers with my methods. Please help.
 

KFunk

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Trebla said:
From three collinear points, A, B, and C on the ground, the angles of elevation of the top of a mast are 30 degrees, 45 degrees and 60 degrees respectively. if AB = 90m and BC = 150m, find the exact height of the mast.

I keep getting undefined answers with my methods. Please help.
Let the top of the mast be H and the point vertically below it be D.


In ΔABH we have sin30°/BH = sin15°/90 ---> BH = 90sin30°/sin15°

In Δ BDH (right angled) we have sin45° = h/BH ---> BH = h/sin45° where h is the height of the mast.

combining both we have: h = 90sin30°sin45°/sin15°
 

Trebla

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KFunk said:
In ΔABH we have sin30°/BH = sin15°/90 ---> BH = 90sin30°/sin15°
I don't understand how you got this bit and how you got sin 15.
 

香港!

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Trebla said:
I don't understand how you got this bit and how you got sin 15.
I haven't read or tried to do the question, but that looks like it comes from the sin rule?
(sinA)\a=(sinB)\b
 

Trev

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I did this:
tan30° = 1/√3 = h/(240+x) [1]
tan45° = 1 = h/(x+150) [2]
tan60° = √3 = h/x [3]

Combining [1] and [3] gives:
(240+x)/√3 = x√3
240+x=3x
x=120

Using [2]
h = 250+120 = 270m
 

Trebla

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What The Hell!!! Why Has Everyone Got Different Answers Yet With Reasonable Methods???!!!!!
 

KFunk

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Because I made the invalid assumption that A, B and C are in line with the mast :p. Go with brett's method, it's solid.
 

Trebla

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So is it a 2D or 3D question? Both of them end up with different answers.
 
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acmilan

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Depends on interpretation. Seeing as how its a 3 unit question, it most likely is a 3D question.
 

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