3D vector question (1 Viewer)

KevDa5'9"

New Member
Joined
Apr 24, 2020
Messages
12
Gender
Male
HSC
2021
Hello, I did this 3D vector question but my answer for 4b didn't match the textbook's answer.

4a. Find the equation of the line that goes through A(8,-14,-2) and the point of intersection B of the lines L1: (x-7)/-2 = (y+3)/5 = z-1 and L2: x-8 = (y+1)/-4, z+1=0.
Answer: p = (8i - 14j - 2k) + u(3i + j + k)

4b. Hence, by observing the direction vectors of the lines AB and L1, find the equation of the plane that contains point A and the line L1.
My answer: 4x+5y-17x = -2
Textbook answer: 3x+y+z=10

I checked my answer with GeoGebra but was still unsure.
Any help would be greatly appreciated.
 

B1andB2

oui oui baguette
Joined
Nov 6, 2019
Messages
576
Location
cuddles lane
Gender
Undisclosed
HSC
N/A
I got your answer too by dot product-ing a normal (a,b,c) with direction vector AB and the line and finding a,b,c for the plane equation
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top