Hello, I did this 3D vector question but my answer for 4b didn't match the textbook's answer.
4a. Find the equation of the line that goes through A(8,-14,-2) and the point of intersection B of the lines L1: (x-7)/-2 = (y+3)/5 = z-1 and L2: x-8 = (y+1)/-4, z+1=0.
Answer: p = (8i - 14j - 2k) + u(3i + j + k)
4b. Hence, by observing the direction vectors of the lines AB and L1, find the equation of the plane that contains point A and the line L1.
My answer: 4x+5y-17x = -2
Textbook answer: 3x+y+z=10
I checked my answer with GeoGebra but was still unsure.
Any help would be greatly appreciated.
4a. Find the equation of the line that goes through A(8,-14,-2) and the point of intersection B of the lines L1: (x-7)/-2 = (y+3)/5 = z-1 and L2: x-8 = (y+1)/-4, z+1=0.
Answer: p = (8i - 14j - 2k) + u(3i + j + k)
4b. Hence, by observing the direction vectors of the lines AB and L1, find the equation of the plane that contains point A and the line L1.
My answer: 4x+5y-17x = -2
Textbook answer: 3x+y+z=10
I checked my answer with GeoGebra but was still unsure.
Any help would be greatly appreciated.