M mathsbrain Member Joined Jul 16, 2012 Messages 162 Gender Male HSC N/A Jun 18, 2014 #1 How do one sketch 0< arg(z(1+i)) < pi/2 Last edited: Jun 18, 2014
rumbleroar Survivor of the HSC Joined Nov 30, 2011 Messages 2,271 Gender Female HSC 2014 Jun 18, 2014 #2 ?? what's your question?
RealiseNothing what is that?It is Cowpea Joined Jul 10, 2011 Messages 4,591 Location Sydney Gender Male HSC 2013 Jun 18, 2014 #3 mathsbrain said: How do one sketch $0<arg((1+i)z)<pi/2$ Click to expand... Remember Simplify the inequality.
mathsbrain said: How do one sketch $0<arg((1+i)z)<pi/2$ Click to expand... Remember Simplify the inequality.
M mathsbrain Member Joined Jul 16, 2012 Messages 162 Gender Male HSC N/A Jun 18, 2014 #4 sorry had a few issues with typeset
M mathsbrain Member Joined Jul 16, 2012 Messages 162 Gender Male HSC N/A Jun 18, 2014 #5 yeah that gives me -pi/4< arg(z) < pi/4 but on wolfram alpha it gave me something weird, try typing "arg(z(1+i))< pi/2" and see the plot that wolfram alpha returns
yeah that gives me -pi/4< arg(z) < pi/4 but on wolfram alpha it gave me something weird, try typing "arg(z(1+i))< pi/2" and see the plot that wolfram alpha returns
M mathsbrain Member Joined Jul 16, 2012 Messages 162 Gender Male HSC N/A Jun 18, 2014 #6 does it have something to do with principal argument in this case?
RealiseNothing what is that?It is Cowpea Joined Jul 10, 2011 Messages 4,591 Location Sydney Gender Male HSC 2013 Jun 19, 2014 #7 wolframalpha interprets it differently what you have is correct, just sketch it