A few complex number qs (1 Viewer)

5uckerberg

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For d when you have this implies that you need to double the argument to obtain the arg of z so in turn

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Thus,
 

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I got that but in the solution for some reason they also drew in (-2pi/3)
 

yanujw

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I got that but in the solution for some reason they also drew in (-2pi/3)
This is because squaring complex nos with arg (-2pi/3) gives them an arg of -4pi/3, which is an equilvalent arg to 2pi/3 and therefore satisfies the condition.
 

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ohh okay I see but how would you get that working from pi/3
 

5uckerberg

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De Moivre's Theorem that is what is happening squaring the angle doubles the angle of rotation and so on.
 

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I still can't see it for some reason
 

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