davidbarnes
Trainee Mȯderatȯr
Can anyone tell me how i woudl solve the following, which have got me stumped. Any help is needed as the exam is soon. Thankyou.
![](/proxy.php?image=http%3A%2F%2Fimg528.imageshack.us%2Fimg528%2F8413%2Fsaveuo2.jpg&hash=e7eea64ed26dbe2944d3f87f9a2aca06)
is this valid? if it is then you just gotta remember x =/= -3 (can't divide by zero) so its a discontinuous line with no solution where x = -3.darkliight said:3. y = (x^2 + 3x)/(x + 3) = x(x+3)/(x+3) = x ... graph me.