For b, count the longest chain (7). Both the branches leading off are methyl groups, so you’ll end up with 3,5-dimethyl-heptane
For c, prioritise the triple bond that makes it an alkyne, count the longest chain from there, and add the substituent. Note that there will be a carbon at the beginning and end of the triple bond (before it connects to where you wrote 5). In this case, it will be called 3-butyl-1-octyne
For d, well, this is one I think you just have to know and be able to recognise; it’s benzene
I’ve attached screenshots where I have drawn around the longest chain for your reference. Hope this helps