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A tricky log question (1 Viewer)

angels heap

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Hey could someone please do:

logx32 x log3m (divide sign) log3125

In writing that is:

[log (base x) 32] times [log (base 3) m] divide [log (base 3) 125]

If possible could you attach working?

Cheers
 

Riviet

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Don't have time to type it all out, but use the change of base law:
logab = logyb/logya, where y can be any positive integer
 

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