syriangabsta said:
wait sorry now im kinda confused....
so, when the light passes through the flame, what happens? does some of the flames electrons absorb some light? and then the detector absorbs the LEFTOVER light, and uses this info against a callibration curve to determine the amount of cation? :S:S
DIAGRAM:
(cathod ray lamp)------------Flame(acetylene burner)----------(prism/slit)Monochromator--------sensor
EDIT::::::::::::: i just looked it up. the monochromator is the prism/slit which blocks out other wavelengths. The detector is a separate unit called a Photomultiplier Tube PMT which senses the wavelengths exiting the monochromator which would be the wavelength desired (as the monochromator has already remove the unwanted ones)
NOTE: i fixed up my diagram to include this
NOTE: the monochromator aims at only allowing the wavelengths emitted from the lamp (which is absorbed by the cation being tested for-->has been calibrated) to pass through so only those wavelengths are detected. This has something to do with the fact that (as shown in a flame test) when cations move up and down their energy levels (as they absorb the energy from the lamp) they emitt visible light (if they are able to) in the process. The monochromator(slit/prism) prevents this visible light/any other visible light and wavelengths in its environment from passing through and being detected. I guess they must have to calibrate the monochromator to "tell it" which wavelength to allow (i.e. the wavelength absorbed by the cation being tested for).
The wavelengths shon from the calibrated cathode ray through the burner(i.e. flame), pass through the monochromator (filters wavelengths) and is recorded by the PMT. Along the way, the sample to be tested is injected into the flame, where it is vaporised (the solvent removed i.e. water) and the cations (we're not concerned with anions) in gaseous form remain. As the sample is vaporised in the flame and the solvent is removed, when the constituents turn into gaseous cations they are quickly "exited" by the wavelengths being shon from the lamp as they aborb the lamp's wavelengths and then (i think once the lamp is turned off or i dont know how long after) they return to their normal energy levels. All the while, the monochromator has been filtering the wavelengths being recieved on the other side of the burner(flame) - there will be less as the cations have absorbed some when they were exited. Hence why the less wavelengths recieved by the sensor(PMT) = the more absorbed = the higher the concentration
Now, from what i gather, the cations do not get exited by the burnet(flame). The flame acts as the utensil which removes the solvent so the cations can become gaseous cations which can then be exited by the lamp's wavelengths.
i think that answers your question.
oh yeh lol the flames electrons dont absorb energy (i think you mean the flames molecules as electrons dont absorb energy, the atom absorbs it and the electrons within the atom are exited i.e. have enough energy to raise a shell)