airie
airie <3 avatars :)
ie. When the object ends up being lower than its starting point, vertically. The object doesn't have to end up on the ground, actuallyIceOnFire said:What's "when the point of launch is above ground level?"
Basically use the delta(y)=uyt+0.5ayt2 and delta(x)=uyt for the positions, and use v2=u2+2ar in both the horizontal and vertical directions (well, but really, vx would be just the same as ux), then use Pythagoras to find the overall velocity, and trig (just tan, really) for the angle it makes with the horizontal.IceOnFire said:and "Find the position of the object and its instantaneous velocity at a given time?" ? How do you find them? I haven't seen any questions related to them... yet.
EDIT: 800th post! XD
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