Just algebra I think...
Multiply the first equation by x and the second by y. This gives,
y2x2 = 15x3 + 17x2y + 15y2x
x2y2 = 20x2y + 3y3.
That is,
15x3 + 17x2y + 15y2x = 20x2y + 3y3.
Rearranging gives
-x2(y-5x) = y2(y-5x).
So either x = y = 0 (which we don't want) or y - 5x = 0 => y = 5x.
Sub this into the second equation to get
5x3 = 95x2 => x2(5x-95) = 0 => x = 19 => y = 95.
The required sum follows.