AIMO Question which is bugging me (1 Viewer)

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Find x + y where x and y are non-zero solutions of the system of equations:
y2x = 15x2 + 17xy + 15y2
x2y = 20x2 + 3y2

I'm fairly sure the solution is x=19 and y=95. Just don't know how to get there.
 

darkliight

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Just algebra I think...

Multiply the first equation by x and the second by y. This gives,
y2x2 = 15x3 + 17x2y + 15y2x
x2y2 = 20x2y + 3y3.

That is,
15x3 + 17x2y + 15y2x = 20x2y + 3y3.

Rearranging gives
-x2(y-5x) = y2(y-5x).

So either x = y = 0 (which we don't want) or y - 5x = 0 => y = 5x.
Sub this into the second equation to get
5x3 = 95x2 => x2(5x-95) = 0 => x = 19 => y = 95.

The required sum follows.
 

tehcreativ1

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darkliight said:
Just algebra I think...

Multiply the first equation by x and the second by y. This gives,
y2x2 = 15x3 + 17x2y + 15y2x
x2y2 = 20x2y + 3y3.

That is,
15x3 + 17x2y + 15y2x = 20x2y + 3y3.

Rearranging gives
-x2(y-5x) = y2(y-5x).

So either x = y = 0 (which we don't want) or y - 5x = 0 => y = 5x.
Sub this into the second equation to get
5x3 = 95x2 => x2(5x-95) = 0 => x = 19 => y = 95.

The required sum follows.
Yup, darkliight's solution is awesome =D just a note that the first step (multiplying through to get equivalent expressions) can only be done coz x and y are nonzero. otherwise, yay for darkliight and yay for aimo ^^
 

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