B blacksriders New Member Joined Sep 9, 2008 Messages 6 Gender Female HSC 2004 Nov 2, 2008 #1 For what value of k will thee equation x^2 - (k+2)x + (k-4) = 0 have .. one root equal to zero ?
Trebla Administrator Administrator Joined Feb 16, 2005 Messages 8,391 Gender Male HSC 2006 Nov 2, 2008 #2 If one root equals zero, then the constant must the zero i.e. k - 4 = 0 => k = 4
B blacksriders New Member Joined Sep 9, 2008 Messages 6 Gender Female HSC 2004 Nov 2, 2008 #3 What if one of the root was = 4 ?
T Timothy.Siu Prophet 9 Joined Aug 6, 2008 Messages 3,449 Location Sydney Gender Male HSC 2009 Nov 2, 2008 #4 blacksriders said: What if one of the root was = 4 ? Click to expand... x^2 - (k+2)x + (k-4) = 0 a+b=k+2 ab=k-4 if a=4 4+b=k+2 and 4b=k-4 b=k-2 sub into the other one 4k-8=k-4 3k=4 k=4/3 (doesn't look right)
blacksriders said: What if one of the root was = 4 ? Click to expand... x^2 - (k+2)x + (k-4) = 0 a+b=k+2 ab=k-4 if a=4 4+b=k+2 and 4b=k-4 b=k-2 sub into the other one 4k-8=k-4 3k=4 k=4/3 (doesn't look right)
Trebla Administrator Administrator Joined Feb 16, 2005 Messages 8,391 Gender Male HSC 2006 Nov 2, 2008 #5 blacksriders said: What if one of the root was = 4 ? Click to expand... Is this a separate question? If it is, just sub x = 4 into the equation and solve for k.
blacksriders said: What if one of the root was = 4 ? Click to expand... Is this a separate question? If it is, just sub x = 4 into the equation and solve for k.
T Timothy.Siu Prophet 9 Joined Aug 6, 2008 Messages 3,449 Location Sydney Gender Male HSC 2009 Nov 2, 2008 #6 Trebla said: Is this a separate question? If it is, just sub x = 4 into the equation and solve for k. Click to expand... or that, much easier, silly me
Trebla said: Is this a separate question? If it is, just sub x = 4 into the equation and solve for k. Click to expand... or that, much easier, silly me