Smilebuffalo
Member
An object is projected with horizontal velocity 8ms^-1 and vertical velocity 5ms^-1. Find the range of its flight. (use g = 10ms^-2)
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Another projectile motion Q. (1 Viewer)
- Thread starter Smilebuffalo
- Start date
davidgoes4wce
Well-Known Member
Vertical Component
ÿ=-10
ẏ=∫ -10 dt= -10t + C
t=0 y=5
C=5
ẏ=-10t + 5
y=∫-10t+5 dt
y=-5t^2+5t+C
t=0,y=0
C=0
y=-5t^2+5t
let y=0
0=-5t(t-1)
t=1
Horizontal Components
ẍ=0
ẋ=∫ 0 dt= 0t +C
when t=0, ẋ=8
ẋ=8
x=∫8 dt
when t=0, x=0
x=8t+ C
C=0
x=8t
let t=1
x=8*1=8 metres
ÿ=-10
ẏ=∫ -10 dt= -10t + C
t=0 y=5
C=5
ẏ=-10t + 5
y=∫-10t+5 dt
y=-5t^2+5t+C
t=0,y=0
C=0
y=-5t^2+5t
let y=0
0=-5t(t-1)
t=1
Horizontal Components
ẍ=0
ẋ=∫ 0 dt= 0t +C
when t=0, ẋ=8
ẋ=8
x=∫8 dt
when t=0, x=0
x=8t+ C
C=0
x=8t
let t=1
x=8*1=8 metres
KloppsAndRobbers
Active Member
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- 2024
There's no need for sin or cos because the velocities are already given.