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Answering any General Mathematics! (1 Viewer)

tomholman

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Hey everyone. I'd love to give back to all those battling through HSC general mathematics this year! I came 12th in the State for General Mathematics in 2014 and I have a whole range of resources and tutoring experience.

Post away!
 

SudhiTheBoat

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Hey man, what was your raw mark? And approximate marks at school if you remember?
 

DiZ

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Sup! Just a question for probability.
I have the answer, but I have no idea how to do the working out for it.

David chooses five cards from a normal pack of 52 playing cards.
a) How Many different selections are possible (no need to do this one, I get how to do this type of question.)
b) How many five-card hands will have exactly one ace?
c) How many five-card hands will have exactly two aces?

b and c are the ones I can't work out.

Many Thanks.
 

Xstudying

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Need help in my assignments questions... Anyone? Doing my last assessment for general maths
 

Zoinked

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Sup! Just a question for probability.
I have the answer, but I have no idea how to do the working out for it.

David chooses five cards from a normal pack of 52 playing cards.
a) How Many different selections are possible (no need to do this one, I get how to do this type of question.)
b) How many five-card hands will have exactly one ace?
c) How many five-card hands will have exactly two aces?

b and c are the ones I can't work out.

Many Thanks.
Correct me if I'm wrong, its been a while since general lol.
b) You know that there are four aces in a deck and the hand can only have one, which means after choosing your ace, there are 48 cards remaining. 4x48x47x46x45 should give you the answer.
c) 4x3x48x47x46.

That should be how its done (work these out and check the answers).
 

InteGrand

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Dec 11, 2014
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Sup! Just a question for probability.
I have the answer, but I have no idea how to do the working out for it.

David chooses five cards from a normal pack of 52 playing cards.
a) How Many different selections are possible (no need to do this one, I get how to do this type of question.)
b) How many five-card hands will have exactly one ace?
c) How many five-card hands will have exactly two aces?

b and c are the ones I can't work out.

Many Thanks.
Correct me if I'm wrong, its been a while since general lol.
b) You know that there are four aces in a deck and the hand can only have one, which means after choosing your ace, there are 48 cards remaining. 4x48x47x46x45 should give you the answer.
c) 4x3x48x47x46.

That should be how its done (work these out and check the answers).
You've done your answers assuming there's an order that matters for the cards, but for a hand, the order doesn't matter, so we should take this into account.











 

fluffchuck

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Apr 29, 2016
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2017
You've done your answers assuming there's an order that matters for the cards, but for a hand, the order doesn't matter, so we should take this into account.











Ooh very nice, I think you should explain to them what the binomial expressions mean (general doesn't cover it).
 

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